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Flappy Joe
06-23-2012, 04:24 PM
Hey guys, I want to start a thread with really hard questions.

Feel free to add your own once the one before you has been answered.


RULES
DO NOT USE A CALCULATOR
DO NOT USE GOOGLE
OBEY THE ABOVE 2 SENTENCES


This may not be hard for some of you, but answer this:

sqrt(-1)
Jah
06-23-2012, 05:05 PM
sqrt(-1) = i?
HolmaN
06-23-2012, 05:10 PM
sqrt(-1) = i?

https://www.google.se/#hl=sv&output=search&sclient=psy-ab&q=sqrt%28-1%29+%3D+&oq=sqrt%28-1%29+%3D+&aq=f&aqi=g-K4&aql=&gs_l=hp.3..0i30l4.282.282.0.468.1.1.0.0.0.0.52.52. 1.1.0...0.0.0AKsqgg1O94&pbx=1&bav=on.2,or.r_gc.r_pw.r_qf.,cf.osb&fp=de61459d93dfbc78&biw=1600&bih=792
Jah
06-23-2012, 05:26 PM
https://www.google.se/#hl=sv&output=search&sclient=psy-ab&q=sqrt%28-1%29+%3D+&oq=sqrt%28-1%29+%3D+&aq=f&aqi=g-K4&aql=&gs_l=hp.3..0i30l4.282.282.0.468.1.1.0.0.0.0.52.52. 1.1.0...0.0.0AKsqgg1O94&pbx=1&bav=on.2,or.r_gc.r_pw.r_qf.,cf.osb&fp=de61459d93dfbc78&biw=1600&bih=792

http://lmgtfy.com/?q=Sshh%2C+shut+the+fuck+up+%3B(
Flappy Joe
06-23-2012, 05:34 PM
I said don't use google and you did, well done faggot.
Jah
06-23-2012, 06:33 PM
I said don't use google and you did, well done faggot.

Evidence please.
Anyhow.

How does the vector change by A*u if A=
|cos v -sin v|
|sin v cos v|
Also calculate A^2
Bushu
06-23-2012, 06:46 PM
What.The.Fuck.Are.You.Talking.About.
Niyar
06-23-2012, 07:14 PM
What.The.Fuck.Are.You.Talking.About.
Uhh.. Yeah! Like that explain please! :D
Jah
06-23-2012, 07:34 PM
u = (r cost, r sint)
where r = | U | and T is the angle u allows the x-axis. The product Au is thus
Au = (r (cosvcost-sinvsint), r (+ sinvcost cosvsint)) = (r cos (w + t), r sin (w + t)),
ie the vector u rotated v radians counterclockwise.
kimfinnstrom
06-23-2012, 08:06 PM
I think JOker did not cheat :O
Stusse
06-23-2012, 08:24 PM
How about sqrt of -1 doesnt exist due to nothing can be multiplied with itself and being less than 0.

Or is it too unacademical answer? ;p
Luls
06-23-2012, 10:03 PM
How about sqrt of -1 doesnt exist due to nothing can be multiplied with itself and being less than 0.

Or is it too unacademical answer? ;p

That's where imaginary numbers come into play. sqrt of -1 = i is something actually fairly basic math, depending on the math course you take.



I said don't use google and you did, well done faggot.


It's common knowledge for like, grade 10+ math, how is that google? o.O
Flappy Joe
06-23-2012, 10:51 PM
Brandon, he used google and I know it.

smd obviously I own you all....