for genius ppl and programmers help with this dilemma

sorry to waste ur time but i rly need help with this and i thought some genius and programmers are here in the forum it might be easy thing for them

i am organizing a tournament for a game for the best 8 players in my country
it is a league and it is played in couples in which all couples need to meet the others
ex : player 1 , p2 has to meet 3-4 and 3-5 and 3-6 and 3-7 and 3-8 and 4-5 ,4-6 4-7 , 4-8 ,5-6 , 5-7 ,5-8, 6-7, 6-8, 7-8
then player 1-3 has to meet 2-4 , 2-5 etc
this is gonna be a total of 210 game so lets assume 1-2 vs 3-4 , on the other table 5-6 vs 7-8 ( this = 2 games = 1 round ) so this is total 105 rounds

we want the tournament to be 7 rounds /day for 15 days
in which every player daily has to meet all players twice and play with him once example : player 1 will play 7 games / day , one game with ( 2-3-4-5-6-7-8) and meet versus each player twice

i think it is mathematically possible , but my brain is about to blow up
please if u think u can help post something for me , or if u read that and think someone can help tag him please

That makes no sense. Elaborate. And What do you need? A program? An Excel file?...

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Originally Posted by satoshi

That makes no sense. Elaborate. And What do you need? A program? An Excel file?...

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i believe someone good with programming can help me with it

I don't really understand how it would be 210 matches to be honest.

Are there fixed couples? like player 1 always plays together with player 2 and needs to meet the couples p3p4, p5p6 and p7p8? - 4 couples which would result in 6 matches.

Or does every player play together with all of the others and play against any other possible couple? - Meaning 28 possible couples and 378 matches

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Originally Posted by SmegOut

I don't really understand how it would be 210 matches to be honest.

Are there fixed couples? like player 1 always plays together with player 2 and needs to meet the couples p3p4, p5p6 and p7p8? - 4 couples which would result in 6 matches.

Or does every player play together with all of the others and play against any other possible couple? - Meaning 28 possible couples and 378 matches

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no p1p2 vs p3p4 , p3p5 ,p3p6 ,p3p7 ,p3p8 , p4p5 , p4p6 until they reach p7p8 >> total 15 game
then p1p3 vs p2p4 until reach p7p8 total 15 game
p1p4 vs p2p3 ,p2p5 and so on 15 game too
p1p8 and so on which mean p1 play 15 game with every player and same for every single player

which mean every player will play 105 game and i want him to finish on 15 day , every player plays 7 games /day every game with different player , and he should meet p2 and p3 an p4 and p5 and p6 and p7 and p8 twice each
i hope i have explained
btw it is 28 couples right but only 210 match because some games cant be played like p1p2 vs p2p3 ( p2 cant play on both sides at same time :))
btw are u smeg ? if so welcome back man

bump come on genius ppl give it a look

Don't really know why I did this, since it's not the solution. But well I made it now anyways, so might as well post it:

Possible couples:
http://gyazo.com/a8bd46d182f061a809e7ef60fb8ab589

Possible matches (pick either side of the table):
http://gyazo.com/738d69d1685c5b01d7dc8afc09726020

If the excel file is usefull to you pm me your e-mailadres and I'll send you the file, if not goodluck fixing this challenge :D

P.s yes it's smeg :p

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Originally Posted by SmegOut

Don't really know why I did this, since it's not the solution. But well I made it now anyways, so might as well post it:

Possible couples:
http://gyazo.com/a8bd46d182f061a809e7ef60fb8ab589

Possible matches (pick either side of the table):
http://gyazo.com/738d69d1685c5b01d7dc8afc09726020

If the excel file is usefull to you pm me your e-mailadres and I'll send you the file, if not goodluck fixing this challenge :D

P.s yes it's smeg :p

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these are possible outcomes, i already went this far
but i rly appreciate u gave it time
thank youuuuuuuuuu

Quote:

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Originally Posted by masterofpacera

these are possible outcomes, i already went this far
but i rly appreciate u gave it time
thank youuuuuuuuuu

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Possible matches that can be played simultaniously can be defined manually pretty easily as well:
1234 - 5678
1324 - 5768
1423 - 5867
etc..

It's quite time consuming though to define which matches can be played in the same round. Don't know if it also can be done automatically, since I'm not a genius after all :D

Would be nice to know if there's some sort of formula to check if there are multiple numbers within a value though.

I dont see why doing it so hard?
Just make 1 schedule and repeat that untill everyone has been 1 time that number

Here is a schedule with the numbers.
For example on day 1 you appoint like:
1 = person a
2 = person b
3 = person c
etc
On day 2 you switch every person and his number, so:
1 = person b
2 = person c
3 = person d
etc
http://puu.sh/bvPNL/461527c85e.png

Actually i made a small error hold on i`ll get you the right schedule xD

Quote:

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Originally Posted by xux

Actually i made a small error hold on i`ll get you the right schedule xD

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ok bro i am excited to hear ur idea it maybe a fix after all

There this schedule is fixed better :P
http://puu.sh/bvRum/3530c144a2.png

Quote:

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Originally Posted by xux

There this schedule is fixed better :P
http://puu.sh/bvRum/3530c144a2.png

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Oh wait i should have read better its a pair league tum tum tuuuuuuuuuum my bad :<

Quote:

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Originally Posted by xux

Oh wait i should have read better its a pair league tum tum tuuuuuuuuuum my bad :<

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Ok i`m out to hard :<

i did fill in 1 total match up for 1 day :p

so if you mix it up you should be able to do it xD

@masterofpacera

If you use this format:
http://puu.sh/bvTPg/8dd44fbcce.png

Just make 1 schedule and repeat that untill everyone has been 1 time that number
For example on day 1 you appoint like:
1 = person a
2 = person b
3 = person c
etc
On day 2 you switch every person and his number, so:
1 = person b
2 = person c
3 = person d

Then you might have had them all xD

Quote:

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Originally Posted by xux

@masterofpacera

If you use this format:
http://puu.sh/bvTPg/8dd44fbcce.png

Just make 1 schedule and repeat that untill everyone has been 1 time that number
For example on day 1 you appoint like:
1 = person a
2 = person b
3 = person c
etc
On day 2 you switch every person and his number, so:
1 = person b
2 = person c
3 = person d

Then you might have had them all xD

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i will try that later tonight and see , if it worked , i will owe u a favor bro
but rly anyway thanks for all the effort and time u did